檢測(cè)UE cap，發(fā)現(xiàn)UE支持Utra_128測(cè)量，然后檢測(cè)UE支持測(cè)量band class，發(fā)現(xiàn)支持

SupportedBandUTRA-TDD128 ::=     ENUMERATED {

                                     a, b, c, d, e, f, g, h, i, j, k, l, m, n,

                                     o, p, ...}

中0和5（即a和f）。但是在匹配eNb支持測(cè)量的3G小區(qū)頻點(diǎn)的時(shí)候，

U16 dlArfcnUTRATDD128[6][2]={
                                       {10054,10121},
                                       {9654,9946},
                                       {9554,9646},
                                       {12854,13096},
                                       {11504,11996},
                                       {9404,9596}
                                    };

   for(idx =0 ;idx < 6 ;idx++)
   {
      if(arfcn >= dlArfcnUTRATDD128[idx][0] &&
            arfcn <= dlArfcnUTRATDD128[idx][1])
      {
         *result = idx +1;
         break;
      }
   }

最后，idx為什么要+1？？？？這樣匹配的result（band class）和a，f匹配還對(duì)嗎？