1     元組tuple

元組也是一種有序的集合，但不能修改，元組定義的時(shí)候用小括號(hào)，列表用中括號(hào)

In [1]: my_str=("aa",'bb',"cc")                                            

In [2]: my_str[0]   #取第一個(gè)元素                                                       

Out[2]: 'aa'

In [3]: my_str[-1]    #取倒數(shù)第1個(gè)元素                                                     

Out[3]: 'cc'

In [4]: my_str[0]='dd'               #元組不支持修改

---------------------------------------------------------------------------

TypeError                                 Traceback (most recent call last)

<ipython-input-4-51beb6fe0961> in <module>

----> 1 my_str[0]='dd'

TypeError: 'tuple' object does not support item assignment

In [6]: names=[1,'600','500',400,300]              #定義一個(gè)列表

In [7]: my_tuple=(100,200,names)               #定義一個(gè)元組，元素包括一個(gè)列表

In [8]: my_tuple                                                           

Out[8]: (100, 200, [1, '600', '500', 400, 300])

In [9]: my_tuple[2][0]=100       #元組里面的列表的元素可以修改,變的不是元組是列表里面的元素

In [10]: my_tuple                                                          

Out[10]: (100, 200, [100, '600', '500', 400, 300])

  列表和元組的讀取

使用for讀取

In [19]: for i in name:

    ...:     print(i)

    ...:

    ...:

1024

312

10

123

使用while讀取

In [29]: i=0

In [30]: while i<len(name):

    ...:     print(name[i])

    ...:     i+=1

    ...:

1024

312

10

123

In [22]: my_tuple

Out[22]: (100, 200, 300, 400, [1024, 312, 10, 123])

In [23]: for i in my_tuple:

    ...:     print(i)

    ...:

100

200

300

400

[1024, 312, 10, 123]

  range函數(shù)，包頭不包尾，要求range里面結(jié)尾比開始大。range在python2和python3中存在不同

1)     python2

>>> c=range(1,10)

>>> c

[1, 2, 3, 4, 5, 6, 7, 8, 9]

>>> 

2)     python3

>>> c=range(1,10)在PYTHON3 懶加

>>> c

range(1, 10)

>>>